Exam 1

  1. Metainformation

    Tag Value
    fileReliability_vufsw-cronbach's_alpha-1170-en_vufsw-cronbach's_alpha-1170-en
    namevufsw-cronbach's alpha-1170-en
    sectionreliability/analysis/cronbach's alpha
    typeschoice
    solutionFALSE, FALSE, TRUE, FALSE, FALSE
    Typeperforming analysis
    Programcalculator
    LanguageEnglish
    Levelstatistical thinking

    Question

    We investigate survey data of a sample of 239 respondents. Given is the following correlation matrix (Pearson correlation coefficient) of three questions of a scale.


    Item1 Item2 Item3
    Item1
    1


    Item2 .312 1
    Item3 .357 .451 1

    The data furthermore shows that the average correlation between the three items is 0.373. Assume that the variances of the three items are the same. How high is Cronbach’s alpha?


    1. FALSE: 0.877
    2. FALSE: 0.728
    3. TRUE: 0.641
    4. FALSE: 0.942
    5. FALSE: 0.801

    Solution

    You can calculate it with: (3*0,373)/(1+(2*0,373))=0,641
    Cronbach’s alpha can be written as a function of the number of test items and the average inter-correlation among the items. Below, we show the formula for the standardized Cronbach’s alpha:

    Here k is equal to the number of items, r-bar is the average inter-item correlation among the items.
    One can see from this formula that if you increase the number of items, you increase Cronbach’s alpha.  Additionally, if the average inter-item correlation is low, alpha will be low.  As the average inter-item correlation increases, Cronbach’s alpha increases as well (holding the number of items constant).


    1. False
    2. False
    3. True
    4. False
    5. False