Exam 1

  1. Metainformation

    Tag Value
    fileReliability_eur-reliability-211-en_eur-reliability-211-en
    nameeur-reliability-211-en
    sectionReliability/Analysis/Cronbach's alpha
    typenum
    solution5.31
    tolerance0
    TypeCalculate
    ProgramCalculator
    LanguageEnglish
    LevelStatistical Literacy

    Question

    Exams aim at measuring a person’s true score. The accuracy of this measurement of the true score will likely be lower if the reliability of the test is too low. One way to theoretically compensate for this lower accuracy is by calculating the adjusted true score: Xest=x̄+Rxx(Xox̄)X_{est} = x̄ + R_{xx}(X_o-x̄)

    Suppose that the average score of a psychometric exam is 5.8. The reliability of this test is .81 (Cronbach’s alpha); A grade of at least 5.5 is needed to pass the exam.

    Calculate the adjusted true score for a student who has grade 5.2. Round to two decimals


    Solution

    For a student who has a 5.2 the adjusted true score becomes: Xest=5.8+.81(5.25.8)=5.8.486=5.314=5.31X_{est} =5.8 + .81(5.2 - 5.8) = 5.8 - .486 = 5.314 = 5.31