Exam 1

  1. Metainformation

    Tag Value
    fileReliability_eur-reliability-204-en_eur-reliability-204-en
    nameeur-reliability-204-en
    sectionReliability/Analysis/Cronbach's alpha
    typeschoice
    solutionFALSE, FALSE, TRUE, FALSE
    TypeConceptual
    Program
    LanguageEnglish
    LevelStatistical Reasoning

    Question

    According to classical test theory the variance of the observed score is equal to the variance of the true score plus the variance of the error. Which of the following answers is a correct representation of the mathematical proof of this?


    1. FALSE: SXO2=SXT+XE2=S(XT+XE)(XT+XE)=SXT2+XE22XTXE=SXT2+SXE22cXtXE=SXT2+SXE2S^2_{XO} = S^2_{XT+XE} = S_{(XT+XE)(XT+XE)} = S_{X^2_T + X^2_E - 2{XTXE}} = S^2_{XT} + S^2_{XE} -2c_{XtXE} = S^2_{XT} + S^2_{XE}
    2. FALSE: SXO2=SXT+XE2=S(XT+XE)(XT+XE)=SXT2+XE2+XTXE=SXT2+SXE22cXtXE=SXT2+SXE2S^2_{XO} = S^2_{XT+XE} = S_{(XT+XE)(XT+XE)} = S_{X^2_T + X^2_E + XTXE} = S^2_{XT} + S^2_{XE} -2c_{XtXE} = S^2_{XT} + S^2_{XE}
    3. TRUE: SXO2=SXT+XE2=S(XT+XE)(XT+XE)=SXT2+XE22XTXE=SXT2+SXE2+2cXtXE=SXT2+SXE2S^2_{XO} = S^2_{XT+XE} = S_{(XT+XE)(XT+XE)} = S_{X^2_T + X^2_E - 2{XTXE}} = S^2_{XT} + S^2_{XE} +2c_{XtXE} = S^2_{XT} + S^2_{XE}
    4. FALSE: SXO2=SXT+XE2=S(XT+XE)(XT+XE)=SXT2+XE2+2XTXE=SXT2+SXE22cXtXE=SXT2+SXE2S^2_{XO} = S^2_{XT+XE} = S_{(XT+XE)(XT+XE)} = S_{X^2_T + X^2_E + 2{XTXE}} = S^2_{XT} + S^2_{XE} -2c_{XtXE} = S^2_{XT} + S^2_{XE}

    Solution


    1. False
    2. False
    3. True
    4. False