| Tag | Value |
|---|---|
| file | Probability_uva-general-rules-656-en_uva-general-rules-656-en |
| name | uva-general-rules-656-en |
| section | Probability/Elementary Probability/General Rules |
| type | num |
| solution | 0.0025 |
| tolerance | 0 |
| Type | Calculation |
| Language | English |
| Level | Statistical Literacy |
| IRT-Difficulty | 1.857 |
| p-value | 0.8071 |
A factory in Arnhem produces energy-saving light bulbs. The probability of failure is 5%. In a sample we randomly pick two bulbs with put back. In the following table we see that the number of bulbs X that is picked has the following probability distribution:
—————- ——– ——- — TRUE of X 0 1 2 probability 0.9025 0.095 ? —————- ——– ——- —
Here X is a random variable. X = 0 means that the two lamps are not defective; X = 1 means that one of the two is defective; X = 2 means that the two bulbs are both defective. What is the probability that both bulbs are defective? Round to four decimal places.
The correct answer is: 0.0025