Exam 1

  1. Metainformation

    Tag Value
    fileInferential_Statistics_vufsw-pvalue-1184-en_vufsw-pvalue-1184-en
    namevufsw-pvalue-1184-en
    sectioninferential statistics/nhst/p-value
    typeschoice
    solutionFALSE, FALSE, FALSE, TRUE, FALSE
    Typeinterpreting output
    ProgramNA
    LanguageEnglish
    Levelstatistical literacy

    Question

    We run a hypothesis testing for a proportion with the following null and alternative hypothesis:

    H0p = 0.50
    Ha> 0.50

    The observed z-score is -1.88. The corresponding P-value (see Table A: Standard Normal Cumulative Probabilities) is 3.01% (actually 0.0301). This means that there is a 3.01% probability that …


    1. FALSE: the z-score is between -1.88 and 0.00.
    2. FALSE: the z-score is between -1.88 and 1.88.
    3. FALSE: the z-score is -1.88 or higher.
    4. TRUE: the z-score is -1.88 or lower.
    5. FALSE: the z-score is between -1.96 and -1.88.

    1. False
    2. False
    3. False
    4. True
    5. False