| Tag | Value |
|---|---|
| file | Inferential_Statistics_vufsw-pvalue-0033-en_vufsw-pvalue-0033-en |
| name | vufsw-pvalue-0033-en |
| section | inferential statistics/nhst/p-value |
| type | schoice |
| solution | FALSE, FALSE, FALSE, FALSE, TRUE, FALSE |
| Type | calculation |
| Program | calculator |
| Language | English |
| Level | statistical literacy |
A politician claims that the average sick leave among older workers is 10 days per year. A researcher doubts this and suspects that the average number of days older workers are absent due to sickness absence is actually lower. He decides to conduct a survey among a random sample of 100 workers in the Netherlands (n=100) and finds in his sample an average sick leave of 9.2 days. The standard deviation is 3.6 days.
What is the probability of such a sample outcome (or an even more worse sample outcome) if we assume that the politician’s claim is politician is correct?
you can calculate it by 131.313/2564.6 = 0.051 (Sum of squares regression/sum of squares total) 0,051*100%=5,1%