Exam 1

1. Metainformation

   Tag	Value
   file	Inferential_Statistics_vufsw-paired_samples-1147-en_vufsw-paired_samples-1147-en
   name	vufsw-paired samples-1147-en
   section	inferential statistics/parametric techniques/t-test/paired samples
   type	schoice
   solution	TRUE, FALSE, FALSE, FALSE
   Type	performing analysis
   Program	calculator
   Language	English
   Level	statistical thinking

   Question

   30 employees of a multinational filled out a questionnaire twice, which, among other things, recorded how much time (measured in number of minutes per week) employees spend on various activities, such as attending meetings and answering e-mails. The first measurement took place a month prior to an ‘effective meeting’ course, and the second measurement two months after the end of this course. A researcher expects that the course has had an effect and employees spend less time on meetings after the course. Suppose the results below were found. The hypothesis is tested with a significance level of 5% (alpha = 0.05).

   N	mean time (measurement 1)	mean time  (measurement 2)	mean difference	standard error (se) of the mean difference
   30	56.2 minutes per week	51.9 minutes per week	4.3	2.2

   Is the null hypothesis H₀ rejected?

   
   
   1. TRUE: Yes, because: the absolute observed t-value > the critical t-value.
   2. FALSE: No, because : the absolute observed t-value > the critical t-value.
   3. FALSE: Yes, because: the absolute observed t-value < the critical t-value.
   4. FALSE: No, because : the absolute observed t-value < the critical t-value.
   
   

   Solution

   The t value is calculated by t = (mean1  -mean2) / se = 1.95.

   In table B, critical value; df = 29; alpha = 0.05; one sided, thus t = 1.70.

   Thus observed t value > critical t value.

   
   
   1. True
   2. False
   3. False
   4. False