| Tag | Value |
|---|---|
| file | Inferential_Statistics_vufsw-equation-1007-en_vufsw-equation-1007-en |
| name | vufsw-equation-1007-en |
| section | inferential statistics/regression/equation |
| type | num |
| solution | 47.9 |
| tolerance | 0 |
| Type | calculation |
| Program | calculator |
| Language | English |
| Level | statistical literacy |
A researcher relates the number of hours spent practising and the ability to successfully execute a specific skill (e.g. diving, arm stand dive, high board dive) with the use of a linear regression model: the more you practise, the better the performance of the dive.
Calculate the predicted score in a diving competition if they have amassed 250 hours of training. Assume that the slope of hours of training = .1016 on diving performance and the constant = 22.5 in the regression equation. Use only one decimal!
The regression equation is: Diving score = 22.5 + 0.1016*hours
training
If you replace hours with 250: (diving score = 22.5 + 0.1016 * 250),
you will reach the outcome 47.9