Exam 1

1. Metainformation

   Tag	Value
   file	Inferential_Statistics_vufgb-posthoctest-004-en_vufgb-posthoctest-004-en
   name	vufgb-posthoctest-004-en
   section	Inferential Statistics/Parametric Techniques/ANOVA/Post-hoc test, Inferential Statistics/Parametric Techniques/ANOVA/Oneway ANOVA
   type	schoice
   solution	FALSE, FALSE, FALSE, TRUE
   Type	Calculation
   Program
   Language	English
   Level	Statistical Literacy

   Question

   A one-way ANOVA compares the mean values of four groups.

   Calculate the right-hand crossing probability required to construct the Bonferroni intervals for all possible pairs of averages.

   
   
   1. FALSE: 0.0125
   2. FALSE: 0.00833
   3. FALSE: 0.00625
   4. TRUE: 0.00417
   
   

   Solution

   The number of groups is 4. The number of possible pairs is then $(g-1) \times 2 = 3 \times 2 = 6$.

   The Bonferroni corrected alpha level is then $\frac{0.05}{6}$.

   The right-hand crossing probability is half of that, so $\frac{0.05}{(6 \times 2)} = \frac{0.05}{12} = 0.00417$.

   
   
   1. Incorrect
   2. Incorrect
   3. Incorrect
   4. Correct