Exam 1

  1. Metainformation

    Tag Value
    fileInferential_Statistics_vufgb-ftestforcomparingnestedmodels-004-en_vufgb-ftestforcomparingnestedmodels-004-en
    namevufgb-ftestforcomparingnestedmodels-004-en
    sectionInferential Statistics/Regression/Multiple linear regression/F-test for comparing (nested) models, Inferential Statistics/Parametric Techniques/ANOVA
    typeschoice
    solutionFALSE, FALSE, TRUE, FALSE
    TypePerforming analysis, Calculation, Interpreting output
    Program
    LanguageEnglish
    LevelStatistical Thinking

    Question

    Given are the ANOVA tables of two regression models: one model with two predictors, and one model with two predictors and their interaction.

    Use the Model Comparison Test to determine whether there is a significant interaction.


    1. FALSE: F(df1=3,df2=21)=3.16>3.07F(df_{1}=3, \; df_{2}=21)= 3.16 > 3.07, so significant interaction
    2. FALSE: F(df1=1,df2=3)=0.57<10.13F(df_{1}=1, \; df_{2}=3)= 0.57 <10.13, so no significant interaction
    3. TRUE: F(df1=1,df2=21)=1.82<4.32F(df_{1}=1, \; df_{2}=21)= 1.82 < 4.32, so no significant interaction
    4. FALSE: F(df1=1,df2=1)=0.54<161.4F(df_{1}=1, \; df_{2}=1)= 0.54 < 161.4, so no significant interaction

    Solution

    F=[(SSErSSEc)/df1][SSEc/df2]=[(565520)/1][520/21]=4524.76=1.82F= \frac{[(SSE_{r}-SSE_{c})/df_{1}]}{[SSE_{c}/df_{2}]} =\frac{[(565-520)/1]}{[520/21]} = \frac{45}{24.76}=1.82. With df1=1df_{1} = 1 (difference in df’s between complete and reduced model) and df2=21df_{2} = 21 (df of SSE in complete model). Look in the F-table at df1=1df_{1} = 1 and df2=21df_{2}=21 what the critical F-value is, this is 4.32. Founded F < critical F, so adding the interaction-term in model 2 does not lead to significant less error, so there is no significant interaction.


    1. Incorrect
    2. Incorrect
    3. Correct
    4. Incorrect