Exam 1

  1. Metainformation

    Tag Value
    fileDescriptive-statistics_EUR-Descriptive-113-en_EUR-Descriptive-113-en
    nameeur-descriptive-113-en
    sectionDescriptive statistics/Summary Statistics/Measures of Spread/Standard Deviation
    typenum
    solution0.45
    tolerance0
    TypeCalculate
    ProgramCalculater
    LanguageEnglish
    LevelStatistical Literacy

    Question

    On the first question in the exam of course 2.8, 189 students gave a correct answer and 71 students gave an incorrect answer. Suppose we create a variable based on the scores for this exam question, where 0 = incorrect answer and 1 = correct answer.

    What is the standard deviation of this variable?


    Solution

    The standard deviation of this variable is p×(1p)\sqrt{p \times (1 - p)}, where pp is the proportion correct: 189189+71=.73\frac{189}{189+71}= .73. Thus, the standard deviation is .73×(1.73)=.45\sqrt{.73 \times (1 - .73)} = .45 (taking the square root of the variance).